SAEED MDCAT
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Which one is incorrect relation at STP
Avogadro’s number is the number of molecules present in
The volume of oxygen gas is 1.12dm3 at STP , the mass of oxygen approximately is
V (dm3) = mass (g)22.4 = 3211.2 = 161.12 = 1.6
V (dm3) = mass (g)22.4 = 3211.2 = 161.12 = 1.6
V (dm3) = mass (g)22.4 = 3211.2 = 161.12 = 1.6
The number of ions present in 111g of CaCl2 , when fully dissociated in aqueous solution will be
The total number of atoms in 10 g of calcium carbonate is (NA = 6.02 × 1023)
Volume occupied by 7g of N2 present in a mixture
2.24 dm3 of CO2 gas at S.T.P has mass
Which one of the following is correct formula to find number of molecules
Which of the following term is not used for ionic compounds?
Ionic compound cannot exist independently so it’s mass is formula mass, No of particle is called formula unit.
Ionic compound cannot exist independently so it’s mass is formula mass, No of particle is called formula unit.
Ionic compound cannot exist independently so it’s mass is formula mass, No of particle is called formula unit.
Which is correct statement
95% ethanol is called rectified spirit.22.414dm3 is the molar volume at STP.RF have no unit.Quantitative analysis involve four step
95% ethanol is called rectified spirit.22.414dm3 is the molar volume at STP.RF have no unit.Quantitative analysis involve four step
95% ethanol is called rectified spirit.22.414dm3 is the molar volume at STP.RF have no unit.Quantitative analysis involve four step
Elemental analysis is performed to determine
Elemental analysis is technique used to determine type of element in compound.
Elemental analysis is technique used to determine type of element in compound.
Elemental analysis is technique used to determine type of element in compound.
There are different steps in determining the empirical formulaStep I. Calculating the number of gram atom Step II. Determining the atomic ratioStep III. Determining the percentage compositionWhat is the correct sequence of the above steps?
The value of “n” in determining molecular formula is obtained from the relation
The value of “n” in determining molecular formula is obtained from the relation
The value of “n” in determining molecular formula is obtained from the relation
The value of “n” in determining molecular formula is obtained from the relation
The simplest formula of a compound containing 50% of element X (At.wt = 10) and 50% of element Y (At. wt = 20) is
Gram atom of Gram atom of
Atomic ratio X : Y
X2Y
Gram atom of Gram atom of
Atomic ratio X : Y
X2Y
Gram atom of Gram atom of
Atomic ratio X : Y
X2Y
An unknown compound has empirical formula CH3O. Its molar mass is 62g/mole. The compound may be (write formulas)
Molecular formula =
Molecular formula =
Molecular formula =
An acid with molecular mass 104 contains 34.6%C, 3.85% H and rest is O. The molecular formula of acid is
The simplest formula of a compound containing 50% of element X (At.wt = 10) and 50% of element Y (At. wt = 20) is
An unknown compound has empirical formula CH3O. Its molar mass is 62g/mole. The compound may be
When 0.1 kg of CaCO3 is decomposed the CO2 produced occupies a volume at STP
Stoichiometric calculation assume that
A limiting reactant is one which
The reactant which consume earlier and produce small amount of product called limiting reactant
The reactant which consume earlier and produce small amount of product called limiting reactant
The reactant which consume earlier and produce small amount of product called limiting reactant
Which one acts as a limiting reactant when 6g of carbon and 16 g of oxygen react to produce CO2
If a sample of ammonium phosphate, (NH4)3PO4 contains 6 moles of hydrogen atoms. Then number of moles of oxygen atoms in the sample is
A chemist is more interested about _______ to express the efficiency of a chemical process
“X” gram of calcium carbonate was completely burnt in air as . The weight of solid residue formed is 14g. What is value of “X” in grams
Balance chemical equation tells us about
The relation which works best in stoichiometry
The yield which reflects the efficiency of a reaction
How many moles of neutron are present in one mole of heavy water?
79g of KMnO4 contains how many moles of oxygen atoms
A
Which of the following can be used to form a molecular ion
Molecular ion can be produced by high energy ,
and X-rays.
Molecular ion can be produced by high energy ,
and X-rays.
Molecular ion can be produced by high energy ,
and X-rays.
Haemoglobin molecule is _________ times then heavier H2
Haemoglobin is 68,000 times heavier than hydrogen atom and 34,000 heavier than hydrogen molecule.
Haemoglobin is 68,000 times heavier than hydrogen atom and 34,000 heavier than hydrogen molecule.
Haemoglobin is 68,000 times heavier than hydrogen atom and 34,000 heavier than hydrogen molecule.
The formation of which ion is exothermic
When electrons added in gaseous atom it will be exothermic process.(Uni-negative) and di-negative is endothermi
When electrons added in gaseous atom it will be exothermic process.(Uni-negative) and di-negative is endothermic
When electrons added in gaseous atom it will be exothermic process.(Uni-negative) and di-negative is endothermic
Haemoglobin molecule is times heavier than He
Hb is 68,000 times heavier than H-atom
Hb is 68,000 times heavier than H-atom
Hb is 68,000 times heavier than H-atom
An elementary particle is
An elementary particle is a subatomic particle
An elementary particle is a subatomic particle
An elementary particle is a subatomic particle
CN-1 is iso-electronic with
Boron has two stable isotopes, 10B (19%) and 11B (81%) Find the average atomic mass of Boron
Average atomic mass of
Average atomic mass of
Average atomic mass of
Bromine has two isotopes having relative abundance as and the average atomic mass of bromine is about
In nature the ratio of relative percentage abundance of the isotopes 35Cl and 37Cl is_______ respectively
Two or more atoms having same atomic masses but different atomic number are called
18.0g of glucose contains number of hydrogen atoms
18.0g of glucose contains number of hydrogen atoms = 3.6×1023.Calculation:The number of moles of glucose = We know:One molecule of glucose (C6H12O6) contains number of H-atoms = 12So0.1 moles of glucose contains number of H-atoms =
=
=
18.0g of glucose contains number of hydrogen atoms = 3.6×1023.Calculation:The number of moles of glucose = We know:One molecule of glucose (C6H12O6) contains number of H-atoms = 12So0.1 moles of glucose contains number of H-atoms =
=
=
18.0g of glucose contains number of hydrogen atoms = 3.6×1023.Calculation:The number of moles of glucose = We know:One molecule of glucose (C6H12O6) contains number of H-atoms = 12So0.1 moles of glucose contains number of H-atoms =
=
=
Which one has maximum number of atoms
Which of the following contains same number of atoms as 6g of Magnesium?
No of atom of mg No of atom of c
No of atom in 03
No of atom in O
No of atom of Al
No of atom of mg No of atom of c
No of atom in 03
No of atom in O
No of atom of Al
No of atom of mg No of atom of c
No of atom in 03
No of atom in O
No of atom of Al
The number of hydrogen atoms in 36 g of NH4+1 is approximately
Maximum number of molecules will be in
How many moles of neutron are present in one mole of heavy water
D2O = 2+ = 10neutron
D2O = 2+ = 10neutron
D2O = 2+ = 10neutron
3.01×1023 molecules of CO2 are added into 22g of CO2 at STP. The total moles of CO2 become
500 ml of NH3 contains 6.00 × 1023 molecules at S.T.P. How many molecules are present in 100 ml of CO2 at S.T.P?
The volume occupied by 1.6g of O2 at STP is
The volume occupied by 1.6g of O2 at STP is 1.12dm3.We know the molar volume of O2 at STP = 22.414dm3OrOne mole (32g) of O2 at STP = 22.414dm31g of O2 at STP has volume = 22.414dm3 / 32g1.6g of O2 at
The volume occupied by 1.6g of O2 at STP is 1.12dm3.We know the molar volume of O2 at STP = 22.414dm3OrOne mole (32g) of O2 at STP = 22.414dm31g of O2 at STP has volume = 22.414dm3 / 32g1.6g of O2 at
The volume occupied by 1.6g of O2 at STP is 1.12dm3.We know the molar volume of O2 at STP = 22.414dm3OrOne mole (32g) of O2 at STP = 22.414dm31g of O2 at STP has volume = 22.414dm3 / 32g1.6g of O2 at
15 gram of a gas occupies 11.2 dm3 at S.T.P, the gas is
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